[PHP][REGEXP] preg_match_all zwraca TRUE ale złe dane. Opcje

[gu35t2]

witam.
String jest zmienna javascript pobraną z pliku i wygląda następująco:

Kod

var var0 = [ "11296710","na","21,010,200,000","20101121","20100415","20100209","X","rozne dane","na","koty","12:40 am","00:00","2910416169","Nov. 21, 2010","4.2","kol","4.2700","4.2200","251698248","0.0320","d","4.2500","4.2600","4.3000","4.2600","3.1100","5.0700","Feb. 9, 2010","Apr. 15, 2010","na","na","2.56","-0.02","-172.03","0.00","0","0.744 %","4.2","4.3000","20101119","6712","20101119","4.2600","4.2700","4.2200","0.0000","dane firmowe","na","na" ];

Kod php:

[PHP] pobierz, plaintext 
<?php
$s = file_get_contents("./var.txt");
$s = trim($s);
$s = explode("\n",$s);
 
$patt = "/^var var([0-9]){1,2} = \[ ";            // Begin of pattern
for($i=0; $i<=47; $i++){ $patt .= "\"(.*?)\","; }    // Repeat pattern
$patt .= "\"(.*?)\" \]\;$/";                // The end of pattern
 
echo $patt;
# 1 . Nie Dziala
preg_match_All("/^var var([0-9]){1,2} = \[ (\"(.*?)\",){48}\"(.*?)\" \]\;$/ ", $s[0], $matches);
# 2 . Dziala 
preg_match_all($patt, $s[0], $matches1);
 
echo "<pre>";                         
var_dump($s);
print_r($matches);
print_r($matches1);
echo "</pre>";
show_source(__FILE__);
?>
[PHP] pobierz, plaintext 

Pierwszy preg_match_all zwraca mi TRUE ale 'wypluwa' tylko

Kod

Array
(
    [0] => Array
        (
            [0] => var var0 = [ ...... ];
        )

    [1] => Array
        (
            [0] => 0
        )

    [2] => Array
        (
            [0] => "na",
        )

    [3] => Array
        (
            [0] => na
        )

    [4] => Array
        (
            [0] => na
        )

)

Natomiast drugi preg_match_All działa bez zarzutu - wypluwa mi dane znajduje sie w "(.*?)"
Gdzie znajduje się błąd w pierwszym wyrażeniu regularnym?

dzieki

Ten post edytował gu35t2 22.11.2010, 03:22:12