Witam mam taki skrypt
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Ĺšwinek UPLOADER</title>
<link href="style/style.css" rel="stylesheet" type="text/css" />
<script language="javascript" type="text/javascript">
<!--
function startUpload(){
document.getElementById('f1_upload_process').style.visibility = 'visible';
document.getElementById('f1_upload_form').style.visibility = 'hidden';
return true;
}
function stopUpload(success){
var result = '';
if (success == 1){
result = '<span class="msg">Plik został załadowany!
<?php echo "<strong>$filename</strong>"; ?><\/span><br/><br/>';
}
else {
result = '<span class="emsg">BĹ‚Ä…d podczas uploadowania pliku!<\/span><br/><br/>';
}
document.getElementById('f1_upload_process').style.visibility = 'hidden';
document.getElementById('f1_upload_form').innerHTML = result + '<label>File: <input name="myfile" type="file" size="30" /><\/label><label><input type="submit" name="submitBtn" class="sbtn" value="Upload" /><\/label>';
document.getElementById('f1_upload_form').style.visibility = 'visible';
return true;
}
//-->
</script>
</head>
<body>
<div id="container">
<div id="header"><div id="header_left"></div>
<div id="header_main">ĹšWINEK UPLOADER</div><div id="header_right"></div></div>
<div id="content">
<form action="upload.php" method="post" enctype="multipart/form-data" target="upload_target" onsubmit="startUpload();" >
<p id="f1_upload_process">Ĺadowanie...<br/><img src="loader.gif" /><br/></p>
<p id="f1_upload_form" align="center"><br/>
<label>File:
<input name="myfile" type="file" size="30" />
</label>
<label>
<input type="submit" name="submitBtn" class="sbtn" value="Upload" />
</label>
</p>
<iframe id="upload_target" name="upload_target" src="#" style="width:0;height:0;border:0px solid #fff;"></iframe>
</form>
</div>
<div id="footer"></div>
</div>
</body>
który wysyła dane do
<?php
// Edit upload location here
//$destination_path = getcwd().DIRECTORY_SEPARATOR;
$destination_path = "uploads/";
$result = 0;
$target_path = $destination_path . basename( $_FILES['myfile']['name']);
$result = 1;
$filename = $_FILES['myfile']['name'];
}
?>
<script language="javascript" type="text/javascript">window.top.window.stopUpload(
<?php echo $result; ?>);</script>
Lecz w takiej formie jak jest nie może mi wyświetlić w pierwszym skrypcie nazwy uploadowanego pliku tj w 19 linijce.
Ten post edytował furman12 21.02.2010, 17:56:14
[AJAX][PHP]Problem z pobraniem nazwy uploadowanego pliku
21.02.2010, 17:54:11
