[MySQL][PHP]błąd w zapytaniu Opcje

[kingofspace]

mam bład w skrypcie phpbb 2 by przemo od nowości

zapytanie wygląda tak

[PHP] pobierz, plaintext 
		$sql = "SELECT u.user_id
			FROM (" . AUTH_ACCESS_TABLE . " aa, " . USER_GROUP_TABLE . " ug, " . USERS_TABLE . " u)
			WHERE ug.group_id = aa.group_id
				AND u.user_id = ug.user_id
				AND ug.user_pending = 0
				AND u.user_level NOT IN (" . MOD . ", " . ADMIN . ")
			GROUP BY u.user_id
			HAVING SUM(aa.auth_mod) > 0";
[PHP] pobierz, plaintext 

a błąd tak

DEBUG MODE

SQL Error : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' 1)' at line 2

INSERT INTO phpbb_auth_access (forum_id, group_id, auth_mod) VALUES (54, , 1)

Line : 367
File : admin_ug_auth.php

niewiem co jest nietal;/

jeszcze tu mam fragment kodu z zapytaniem

[PHP] pobierz, plaintext 
						$sql_field .= ( ( $sql_field != '' ) ? ', ' : '' ) . 'auth_mod';
						$sql_value .= ( ( $sql_value != '' ) ? ', ' : '' ) . ( ( !isset($update_mod_status[$forum_id]) ) ? 0 : $update_mod_status[$forum_id]);
 
						$sql = "INSERT INTO " . AUTH_ACCESS_TABLE . " (forum_id, group_id, $sql_field)
							VALUES ($forum_id, $group_id, $sql_value)";
[PHP] pobierz, plaintext 

[darko]

[PHP] pobierz, plaintext 
if(is_null($group_id) || $group_id == "") {
  echo "ustaw mnie zanim wstawisz do zapytania";
}
[PHP] pobierz, plaintext