[MySQL][PHP] Połączenie z kilkoma bazami Opcje

[ayo1001]

Cześć, mam taki kod:

[PHP] pobierz, plaintext 
<?php
$host = "localhost";
$user  = "nazwauzytkownika";
$password =  "haslo";
$database1 = "baza1";
$database2 = "baza2";
$dbh1 = new mysqli($host, $user, $password, $database1);
if($dbh1->connect_errno > 0){
    die('Unable to connect to database' . $dbh1->connect_error);
}
 
$dbh2 = new mysqli($host, $user, $password, $database2);
if($dbh2->connect_errno > 0){
    die('Unable to connect to database' . $dbh2->connect_error);
}
?>
[PHP] pobierz, plaintext 

i:

[PHP] pobierz, plaintext 
<?php
$qry=mysql_query("SELECT * FROM articles order by articles.id DESC LIMIT 0, 2", $dbh1);
if(!$qry)
{
die("Query Failed: ". mysql_error());
}
 
while($row=mysql_fetch_array($qry))
{
echo "<div class='klasa'>";
echo '<img src= "./img'.$row['image'].'" />';
echo "<h4>".$row['title']."</h4>";
echo "<p>".substr($row['content'],0,200)."<a href=test.php?id=".$row['id']." > <br><br> TEST</a></p>";
echo "</div>";
}
?>
 
<?php
$qry=mysql_query("SELECT * FROM articles order by articles.id DESC LIMIT 0, 2", $dbh2);
if(!$qry)
{
die("Query Failed: ". mysql_error());
}
 
while($row=mysql_fetch_array($qry))
{
echo "<div class='klasa'>";
echo '<img src= "./img'.$row['image'].'" />';
echo "<h4>".$row['title']."</h4>";
echo "<p>".substr($row['content'],0,200)."<a href=test.php?id=".$row['id']." > <br><br> TEST</a></p>";
echo "</div>";
}
?>
[PHP] pobierz, plaintext 

Wyświetla mi się błąd:

Kod

Warning: mysql_query() expects parameter 2 to be resource, object given in C:\xamp\htdocs\test\index.php on line 2
Query Failed:

Czyli źle jest:

Kod

$qry=mysql_query("SELECT * FROM articles order by articles.id DESC LIMIT 0, 2", $dbh1);

Co trzeba zmienić ?