[PHP]PHP captcha breaker Opcje

[ox1de]

Witam mam pytanie odnoscie jak powinien wygladac kod w php curl ktory po otworzeniu bedzie przechodzil na daną stronę i łamał obrazek captcha w tym przypadku jest on na stalym linku http://timetoexcite.pl/crypt/cryptographp.php?cfg=0&
mam przykladowy kod captcha breakera

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<?php
//Set the header to say what sort of information we are giving the browser
Header ("(anti-spam-content-type:) image/png");
 
//Generate 2 random numbers for use in our encryption
$enc_num = rand(0, 9999); //This number will be encrypted
$key_num = rand(0, 24); //This is used to choose which bit of our string to use in the image
 
//Use these to get a random string of numbers and letters using MD5
//We then cut the 32 char MD5 down to an 8 char string, starting from a random point
$hash_string = substr(md5($enc_num), $key_num, 8);
 
//MD5 the $hash_string variable again
$hash_md5 = md5($hash_string);
 
//Asign it to a session
$_SESSION['captcha'] = $hash_md5;
 
//Create an array of the images available to us as backgrounds
$bgs = array("lipsum.png", "fibres.png", "rainbow.png");
 
//Choose the background image using the handy array_rand function
$background = array_rand($bgs, 1);
 
//Now to start creating the all important image!
//Set the background as our randomly selected image
$img_handle = imagecreatefrompng($bgs[$background]);
 
//Set our text colour to white
$text_colour = imagecolorallocate($img_handle, 255, 255, 255);
 
//Set the font size
$font_size = 5;
 
//Get the horizontal and vertical dimensions of the background image
$size_array = getimagesize($bgs[$background]);
$img_w = $size_array[0];
$img_h = $size_array[1];
 
//Work out the horizontal position
$horiz = round(($img_w/2)-((strlen($hash_string)*imagefontwidth(5))/2), 1);
 
//Work out the vertical position
$vert = round(($img_h/2)-(imagefontheight($font_size)/2));
 
//Put our text onto our image
imagestring($img_handle, $font_size, $horiz, $vert, $hash_string, $text_colour);
 
//Output the image
imagepng($img_handle);
 
//Destroy the image to free up resources
imagedestroy($img_handle);
 
?>
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ale nie wiem jak powinien on wygladac w calosci
pozdrawiam