[PHP]Błąd: Fatal error: Cannot redeclare Opcje

[kubax33]

Znalazłem skrypt, króty oblicza ile minęło dni między jedną data a drugą jednak przy wdrożeniu do skryptu wyskakuje mi błąd:

Gdzie jest knyf?

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Fatal error: Cannot redeclare workDays() (previously declared in /homez.506/pracowni/www/panel/info.inc.php:1) in /homez.506 info.inc.php on line ...
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function workDays($date1, $date2, $withStartDay = false) { 
    $date1=strtotime($date1); 
    $date2=strtotime($date2); 
    if ($date2===$date1 && !$withStartDay) return 0; 
    $char=1; 
    if ($date1>$date2) 
        {$datePom=$date1;$date1=$date2;$date2=$datePom;$char=-1;} 
    $count=0; 
    if (!$withStartDay) 
        $date1=strtotime('+1 day',$date1); 
    $date2=strtotime('+1 day',$date2); 
    $lastYear = null; 
    $hol=array('01-01','05-01','05-03','08-15','11-01','11-11','12-25','12-26'); 
    while ($date1<$date2) { 
        $year = date('Y', $date1); 
        if ($year !== $lastYear){ 
            $lastYear = $year; 
            $easter = date('m-d', easter_date($year)); 
            $date = strtotime($year . '-' . $easter); 
            $easterSec = date('m-d', strtotime('+1 day', $date)); 
            $cc = date('m-d', strtotime('+60 days', $date)); 
            $hol[8] = $easter; 
            $hol[9] = $easterSec; 
            $hol[10] = $cc; 
        } 
        $weekDay=date('w',$date1); 
        $md = date('m-d',$date1);
        if (!($weekDay==0 || $weekDay==6 || in_array($md,$hol) || $year>2010 && $md=='01-06')) {
            $count++; 
        }
        $date1=strtotime('+1 day',$date1); 
    } 
    $count*=$char; 
    return $count; 
} 
 
echo workDays('2007-10-10','2007-10-12'); //wyświetli 2 
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Ten post edytował kubax33 12.04.2012, 19:41:05

[kubax33]

1) aaa wiem:) - przydatny
2) pomogłeś była pętla...

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