[PHP]Gdzie tu jest błąd? Opcje

[Chelo]

Tak jak w temacie:

[PHP] pobierz, plaintext 
if($numer3 == 2) 
{
 
if($xlink1 && $xlink2 && $xlogin && $xhaslo) 
	{
			$sql2ca12 = "SELECT * FROM ap WHERE kto=$userid1 AND sforum=2 AND dzialanie=0 AND link2=$xlink2";
			$ar01 = mysql_query($sql2ca12);
			$suba0 = mysql_fetch_assoc($ar01);
 
 
 
		 if($xlink1 && $xlink2 && $xlogin && $xhaslo && $numer3 == 2 && $suba0['id'] == NULL)
				{			
					$sql2 = "INSERT INTO ap (kto, link1, link2, login, haslo, sforum, bwnr, proxy, linkvia) value 
							($userid1, $xlink1, $xlink2, '$xlogin', '$xhaslo', 2, $xlink1, '$proxy2', '$vial2')";
					$result2 = mysql_query($sql2);				
				}
 
 
 
 
				$sq3 = "SELECT * FROM ap WHERE link1=$xlink1 AND link2=$xlink2 AND login='$xlogin'";
				$result3 = mysql_query($sq3);
				$row3 = mysql_fetch_assoc($result3);
 
				$_SESSION['login1'] = $row3['login'];
				$_SESSION['haslo1'] = $row3['haslo'];
				$_SESSION['proxy1'] = $row3['proxy'];
				$_SESSION['sforum1'] = $row3['sforum'];
				$_SESSION['id1'] = $row3['id'];	
				$nrforum1x = $_SESSION['sforum1'];
				$id3 = $_SESSION['id1'];
 
	$asql = "SELECT * FROM ap WHERE id=$id3";
	$aresult = mysql_query($asql);
	$arow = mysql_fetch_assoc($aresult);
	$brow = $arow['id'];
 
	if ($arow['bwnr'] == $arow['link1'])
		{
			$zmienna00x = 0;
			$bwnr1 = $arow['link2'];
			$nr0x = 0;
		}
	if ($arow['bwnr'] == $arow['link2'])
		{
			$zmienna00x = 0;
			$bwnr1 = 2;
			$nr0x = 1;
		}
	if($arow['bwnr'] == 2)
		{
			$zmienna00x = 1;
			$nr0x = 1;
		}
 
	if($zmienna00x !== 1) 
		{
			include('curl0xap' . '.php');
 
 
			$asql1 = "UPDATE ap SET dzialanie=$nr0x, bwnr=$bwnr1 WHERE id=$brow";
			$aresult1 = mysql_query($asql1);
		}
 
 
 
		}
}
[PHP] pobierz, plaintext 

Skrypt wykona się 1 raz, ale gdy odświeże skrypt, to drugi raz już tego nie wykona.

Proszę o pomoc

[batman]

Gdzie tu jest błąd?

W temacie.
Temat zamykam. Jeśli chcesz, by został otwarty, wyślij PW do dowolnego moderatora z poprawnym tematem.