[PHP]Parse error: syntax error Opcje

[Gman]

Błąd: Parse error: syntax error, unexpected '$image' (T_VARIABLE) on line 5

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else if ( ini_get( "allow_url_fopen" ) == 1 )
    {
        if ( !copy( $thumbnail_link, $upload_path.$thumb_name ) )
        {
            list( $img_width, $img_height, $img_type, $img_attr ) = image           $image = "";
            switch ( $img_type )
            {
            case 1 :
                $image = imagecreatefromgif( $thumbnail_link );
                $ext = ".gif";
                break;
            case 2 :
                $image = imagecreatefromjpeg( $thumbnail_link );
                $ext = ".jpg";
                break;
            case 3 :
                $image = imagecreatefrompng( $thumbnail_link );
                $ext = ".png";
            }
            $resource = @imagecreatetruecolor( $img_width, $img_height );
            if ( function_exists( "imageantialias" ) )
            {
                @imageantialias( $resource, true );
            }
            @imagecopyresampled( $resource, $image, 0, 0, 0, 0, $img_width, $img_height, $img_width, $img_height );
            @imagedestroy( $image );
        }
        $thumb_name = $video_uniq_id."-1".$ext;
        $img_type = 2;
    default :
        switch ( $img_type )
        {
        case 1 :
            @imagegif( $resource, $upload_path.$thumb_name );
            break;
        case 2 :
            @imagejpeg( $resource, $upload_path.$thumb_name );
            break;
        case 3 :
        }
        @imagepng( $resource, $upload_path.$thumb_name );
        break;
        if ( $resource === "" )
        {
            $error = 1;
        }
    }
    return $upload_path.$thumb_name;
 
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[nospor]

Toz masz jak wol napisane, ze nie spodziewaja sie tam DEFAUTL. CZego nie rozumiesz?