[PHP]problem z if Opcje

[wujeksz]

hej,

mam problem.

$result = mysql_query("SELECT FILE_NAME FROM upload_data WHERE USER_ID='$id' AND TYP='$typ' LIMIT 0,1");
if(mysql_num_rows($result)){
echo '<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple/>
<input type="submit"/>
</form>';
}
else {
(IMG:style_emoticons/default/questionmark.gif) (IMG:style_emoticons/default/questionmark.gif) ?
}

Co wpisac w (IMG:style_emoticons/default/questionmark.gif) , aby otrzymac w echo FILE NAME?

Nie moge sobie z tym poradzic.