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Chciałbym prosić o pomoc jak powinnien być zbudowany formularz aby muc wysyłać kilka rekordów na raz do mysql

prosze o napisanie gdzie popełniony jest bład

[PHP] pobierz, plaintext 
<?php
if ($action=="languages" && $do=="edit"){
stdhead("EDIT Language");
begin_frame("EDIT Language");
navmenu();
print"<center>";
 
if ($_POST) 
{
$id = $_GET["id"];
$uri = $_POST["uri"];
 
$name = $_POST["language"];
$charset = $_POST["charset"];
if($uri!='' and $name!='')
{
mysql_query("UPDATE languages SET uri='$uri', name='$name', charset='$charset' WHERE id='$id'") or die(mysql_error());
echo "<font size=2><BR>Language edited <b>Successful</b><BR><BR></font>";
}
else
{
echo "<BR><b>Error</b> empty field!<BR><BR>";
}
}
else
{
$query = "SELECT * FROM languages WHERE lang_id=".$_GET['lang_id']."";
$sql = mysql_query($query);
echo "<form method='post' enctype='multipart/form-dat' action='?action=languages&do=edit'>";
while ($row = mysql_fetch_array($sql)) {
$id=$row['id'];
$lang_id=$row['lang_id'];
$uri=$row['uri'];
$name=$row['name'];
$charset=$row['charset'];
echo"<input type='hidden' name='id' value=$id >";
echo "<B>ID:</B><BR> <input type=text value=$id disabled><BR><BR>
<B>Lang ID:</B><BR> <input type=text value=$lang_id disabled><BR><BR>
<B>Language File:</B><BR> <input type=text name=uri value=$uri disabled><BR><BR>
<B>Language:</B><BR> <input type=text name=language value=$name><BR><BR>
<B>Charset:</B><BR> <input type=text name=charset value=$charset><BR><BR>";
 
} echo"<input type='Submit' value=' Save ' 
style='border-style: solid; border-color: #666666; background-color: #FFFFFF;'/>
</form>";
}
print"</center>";
?>
[PHP] pobierz, plaintext 

Ten post edytował hwao 19.10.2008, 12:00:50