Notice: Undefined variable: post in ... Dlaczego? Dzięki.
<?php $sql = "SELECT * FROM `rewievs` WHERE `tag` LIKE '$adress' AND `ver` = '1' ORDER BY `id` ASC"; $result = $conn->query($sql); while($row = $result->fetch_assoc()) { $content = $row['content']; $post.= $date.' '.$content.'<br /><br />'; } ?>